260=16x^2

Solution for 260=16x^2 equation:

260=16x^2

We move all terms to the left:

260-(16x^2)=0

a = -16; b = 0; c = +260;
Δ = b2-4ac
Δ = 02-4·(-16)·260
Δ = 16640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16640}=\sqrt{256*65}=\sqrt{256}*\sqrt{65}=16\sqrt{65}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{65}}{2*-16}=\frac{0-16\sqrt{65}}{-32}
=-\frac{16\sqrt{65}}{-32}
=-\frac{\sqrt{65}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{65}}{2*-16}=\frac{0+16\sqrt{65}}{-32}
=\frac{16\sqrt{65}}{-32}
=\frac{\sqrt{65}}{-2}
$